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__HCF and LCM Important Formula - Aptitude Questions and Answers.__

**TIPS FOR SOLVING QUESTIONS RELATED TO HCF and LCM:**

**Prime Number:** A prime number is a natural number greater than 1 that has no positive divisors other than 1
and itself.

For example, 2, 3, 5, 7, 11, 13, etc. are prime numbers.

**Co-Prime Number:** Two numbers are said to be relatively prime, mutually prime, or co-prime to each other when they have
no common factor or the only common positive factor of the two numbers is 1.

In other words, two numbers are said to be co-primes if their H.C.F. is 1.

**Factors:** The numbers are said to be factors of a given number when they exactly divide that number.

Thus, factors of 18 are 1, 2, 3, 6, 9 and 18.

**Common Factors:** A common factor of two or more numbers is a number which divides each of them exactly.

Thus, each of the numbers - 2, 4 and 8 is a common factor of 8 and 24.

**Multiple:** When a number is exactly divisible by another number, then the former number is called the multiple of the
latter number.

Thus, 45 is a multiple of 1, 3, 5, 9, 15 and 45.

**Common Multiple:** A common multiple of two or more numbers is a number which is exactly divisible by each of them.

For example, 12, 24 and 36 is a common multiple of 3, 4, 6 and 12.

**Prime Factorisation:**
If a natural number is expressed as the product of prime numbers, then the factorisation of the number is called its prime factorisation.

A prime factorisation of a natural number can be expressed in the exponential form.

For example:

(1) 24 = 2 x 2 x 2 x 3 = 2^{3} x 3.

(2) 420 = 2 x 2 x 3 x 5 x 7 = 2^{2} x 3 x 5 x 7

Express each one of the given numbers as the product of prime factors. The product of least powers/index of common prime factors gives H.C.F. Example I: Find the H.C.F. of 8 and 14 by Prime Factorisation method? Solution: 8 = 2 x 2 x 2 14 = 2 x 7 Common factor of 8 and 14 = 2. Thus, Highest Common Factor (H.C.F.) of 8 and 14 = 2. Example II: Find the H.C.F. of 24, 36 and 72 by Prime Factorisation method? 24 = 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 72 = 2 x 2 x 2 x 3 x 3 H.C.F. of 24, 36 and 72 = Product of common factors with least powers/index = 2 ^{2} x 3^{}Thus, Highest Common Factor (H.C.F.) of 24, 36 and 72 = 12 |

__Method II:__

**Successive Division method-**Divide the larger number by the smaller one. Now, divide the divisor by the remainder. Repeat the process of dividing the preceding number by the remainder last obtained till zero is obtained as remainder. The last divisor is the required H.C.F.

Example I:

Find the H.C.F. of 8 and 14 by Successive Division method?

__8 |__14 | 1

__8__

__6__| 8 | 1

__6__

__2__| 6 | 3

__6__

0

**Least Common Multiple (L.C.M.):**

L.C.M. of two or more given numbers is the smallest number which is divisible by all the given numbers.

Methods of finding the L.C.M. of a given set of numbers:

__Method I: Prime Factorisation method-__

Express each one of the given numbers as the product of prime factors. The product of greatest powers/index of common prime factors gives L.C.M.

Example I:

Find the L.C.M. of 8 and 14 by Prime Factorisation method?

Solution:

8 = 2 x 2 x 2

14 = 2 x 7

L.C.M. of 8 and 14 = Product of all the prime factors of each of the given number with greatest index of common prime factors

= 2

^{3}x 7 = 56.

Thus, L.C.M. of 8 and 14 = 56.

__Method II:__

**Division method-**Find the L.C.M. of 8 and 14 by using Division method?

__2 | 8, 14__

|4, 7

L.C.M. of the given numbers = product of divisors and the remaining numbers = 2 x 4 x 7 = 56.

**Other important formula related to H.C.F. and L.C.M.:**
\begin{aligned}

1) \text{H.C.F. of given fractions} =\\

\left(\frac{\text{H.C.F. of numerator}}{\text{L.C.M. of denominator}}\right) \\

\end{aligned}

\begin{aligned}

2) \text{L.C.M. of given fractions} = \\

\left(\frac{\text{L.C.M. of numerator}} {\text{H.C.F. of denominator}}\right) \\

\end{aligned}
3) Product of two numbers (First number x Second Number) = H.C.F. X L.C.M.

4) H.C.F. of a given number always divides its L.C.M.

5) Largest number which divides x, y, z to leave remainder R in each case = H.C.F. of (x-R), (y-R), (z-R).

6) Largest number which divides x, y, z to leave same remainder = H.C.F. of (y-x), (z-y), (z-x).

7) Largest number which divides x, y, z to leave remainder a,b,c = H.C.F. of (x-a), (y-b), (z-c).

8) Least number which when divided by x, y, z and leaves a remainder R in each case = (L.C.M. of x, y, z) + R